# Line slope calculator 6x+y=16

**Straight line given by points A[1; 10] and B[2; 4]**

## Calculation:

**Slope-intercept form of line:**y = -6x+16

**Canonical form of the line equation:**6x+y-16 = 0

**Parametric form of the line equation:**

x = t+1

y = -6t+10 ; t ∈ R

**Slope:**m = -6

**Slope angle of line: φ =**-80°32'16″ = -1.4056 rad

**X intercept:**x

_{0}= 2.6667

**Y intercept:**y

_{0}= q = 16

**Distance line from the origin:**d

_{0}= 2.6304

**The length of the segment AB: |AB| =**6.0828

**Vector: AB =**(1; -6)

**Normal vector: n =**(6; 1)

**Midpoint of the segment AB: M =**[1.5; 7]

**Perpendicular Bisector equation:**x-6y+40.5 = 0

**Vector OA = (1; 10) ; |OA| = 10.0499**

**Vector OB = (2; 4) ; |OB| = 4.4721**

**Scalar product OA .OB = 42**

**Angle ∠ AOB = 20°51'16″ = 0.364 rad**